Answer:
A biased coin has 0.65 probability of H.
If the coin is tossed 100 times what is the probability there are 65 or less H.
This is clearly binomial with n = 100, p = 0.65. Let X be number of H in 1000 random flips.
P(X<=65) = 0.53756.
The normal approximation mean = 100*0.65 = 65, standard dev = sqrt(100*0.65*0.35)=4.469…..
Using correction for continuity, P(X<=65) = 0.541474.
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Answer:
A biased coin has 0.65 probability of H.
If the coin is tossed 100 times what is the probability there are 65 or less H.
This is clearly binomial with n = 100, p = 0.65. Let X be number of H in 1000 random flips.
P(X<=65) = 0.53756.
The normal approximation mean = 100*0.65 = 65, standard dev = sqrt(100*0.65*0.35)=4.469…..
Using correction for continuity, P(X<=65) = 0.541474.