The volume V of a gas varies inversely as the pressure P on it. If the volume is 240 cm3 under pressure of 30 kg/cm2 , what pressure has to be applied to have a volume of 160 cm3 ?
The volume V varies inversely as the pressure P means when the volume increases, the pressure decreases and when the volume decreases, the pressure increases.
Now write the formula for inverse variation.
PV= k
Substitute 240 for V 30 for P in the formula and find the constant
(240)(30)=k
7200=k
Now write an equation and solve for the unknown.
We have to find the pressure when the volume is 160 cm3 .
So,
(160)(P)=7200 .
Solve for P .
P=7200160 =45
Therefore, pressure 45 kg/cm2 be applied to have a volume of 160 cm3 .
Example 2:
The length of a violin string varies inversely as the frequency of its vibrations. A violin string 14 inches long vibrates at a frequency of 450 cycles per second. Find the frequency of a 12 -inch violin string.
The length( l ) varies inversely as the frequency( f ), when the length increases, the frequency decreases and when the length decreases, the frequency increases.
Now write the formula for inverse variation.
lf=k .
Substitute 450 for f 14 for l in the formula and find the constant.
(450)(14)=k
6300=k
Now write an equation and solve for the unknown.
We have to find the frequency of 12 -inch violin string.
So,
(12)(f)=6300 .
Solve for f .
f=630012 =525
Therefore, 12 -inch violin string vibrates at a frequency of 525 cycles per second.
Answers & Comments
Answer:
The volume V of a gas varies inversely as the pressure P on it. If the volume is 240 cm3 under pressure of 30 kg/cm2 , what pressure has to be applied to have a volume of 160 cm3 ?
The volume V varies inversely as the pressure P means when the volume increases, the pressure decreases and when the volume decreases, the pressure increases.
Now write the formula for inverse variation.
PV= k
Substitute 240 for V 30 for P in the formula and find the constant
(240)(30)=k
7200=k
Now write an equation and solve for the unknown.
We have to find the pressure when the volume is 160 cm3 .
So,
(160)(P)=7200 .
Solve for P .
P=7200160 =45
Therefore, pressure 45 kg/cm2 be applied to have a volume of 160 cm3 .
Example 2:
The length of a violin string varies inversely as the frequency of its vibrations. A violin string 14 inches long vibrates at a frequency of 450 cycles per second. Find the frequency of a 12 -inch violin string.
The length( l ) varies inversely as the frequency( f ), when the length increases, the frequency decreases and when the length decreases, the frequency increases.
Now write the formula for inverse variation.
lf=k .
Substitute 450 for f 14 for l in the formula and find the constant.
(450)(14)=k
6300=k
Now write an equation and solve for the unknown.
We have to find the frequency of 12 -inch violin string.
So,
(12)(f)=6300 .
Solve for f .
f=630012 =525
Therefore, 12 -inch violin string vibrates at a frequency of 525 cycles per second.
Step-by-step explanation:
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