Answer:

Answer:

• Initial pressure of a gas,P1=6 atm.

Given:

• Initial volume of a gas V1=300ml
• Final volume of a gas,V2=1800ml
• Final pressure of a gas,P2=1 atm

To find:

• Initial pressure of a gas,P1=?

Solution:

As we know that,

From the ideal gas equation,

PV=nRT

From this,

P is inversely proportional to the volume at constant temperature.

Now,

P1V1=P2V2

P1×300ml=1×1800ml

P1=1800/300

P1=6 atm

Hence, The initial pressure of a gas is 6atm.

Explanation:

Hope it helps you......

Answer:

P₁ = 6 atmospheres.

Explanation:

Given :-

Initial volume of the gas (V₁) = 300 ml

Final volume of the gas (V₂) = 1800 ml

Final pressure of the gas (P₂) = 1 atm

To find :-

Initial pressure of the gas (P₁)

Solution :-

Using Boyles law :

P₁V₁ = P₂V₂

P₁ × 300 = 1 × 1800

300 P₁ = 1800

P₁ = 1800/300

P₁ = 6

∴ Initial pressure of the gas (P₁) was 6 atmospheres.