Gaide Question 1. What is the total distance travelled? total time of travel displacement? 2. Compute for the speed speed distance 3. Compute for the velocity. velocity displacement was 4. How is speed different from velocity?
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.2) Average speed = distance/total time = 2,000 m/ 45 min = 44.44 m/min. Average velocity = displacement/total time = 0.
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.2) Average speed = distance/total time = 2,000 m/ 45 min = 44.44 m/min. Average velocity = displacement/total time = 0.3) Average speed = (44.44 m/min) * (1 min/60 s) = 0.7407 m/s. Average velocity is still zero.
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Answer:
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.2) Average speed = distance/total time = 2,000 m/ 45 min = 44.44 m/min. Average velocity = displacement/total time = 0.
1) Starting at home and returning to home gives a displacement of zero and distance of 2,000 m.2) Average speed = distance/total time = 2,000 m/ 45 min = 44.44 m/min. Average velocity = displacement/total time = 0.3) Average speed = (44.44 m/min) * (1 min/60 s) = 0.7407 m/s. Average velocity is still zero.