Explanation:
Range of a projectile is given by : R=gu2×sin2θ=105002×sin(2×15)=10250000×1/2=12500m=12. 5km. Was this answer helpful?
Answer:
search-icon-image
Class 11
>>Physics
>>Motion in a Plane
>>Projectile Motion
>>A bullet is fired from a cannon with vel
Question
Bookmark
A bullet is fired from a cannon with velocity 500 ms
1
. If the angle of projection is 15
o
and g=10 ms
−2
, then the range is :
Medium
Updated on : 2022-09-05
Solution
verified
Verified by Toppr
Correct option is B)
Range of a projectile is given by :
R=
g
u
2
×sin2θ
=
10
500
×sin(2×15)
250000×1/2
=12500m=12.5km
hlo dii kaise ho app m chetna
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Explanation:
Range of a projectile is given by : R=gu2×sin2θ=105002×sin(2×15)=10250000×1/2=12500m=12. 5km. Was this answer helpful?
Answer:
search-icon-image
Class 11
>>Physics
>>Motion in a Plane
>>Projectile Motion
>>A bullet is fired from a cannon with vel
Question
Bookmark
A bullet is fired from a cannon with velocity 500 ms
1
. If the angle of projection is 15
o
and g=10 ms
−2
, then the range is :
Medium
Updated on : 2022-09-05
Solution
verified
Verified by Toppr
Correct option is B)
Range of a projectile is given by :
R=
g
u
2
×sin2θ
=
10
500
2
×sin(2×15)
=
10
250000×1/2
=12500m=12.5km
Explanation:
hlo dii kaise ho app m chetna