Answer:

• The mass of water required to heat the radiator is 3.338 kg

Explanation:

Given;

Quantity of heat supplied to raise the temperature of radiator, Q = 4.05 x 10⁵ J  

Specific heat capacity of water, c = 4.184 J.g⁻¹.C⁻¹ = 4.184 x 10³ J.kg⁻¹C⁻¹  

Quantity of heat supplied to raise the temperature of water;  

Q = mcΔθ  

Where;  

m is the mass of water

c is the specific heat capacity of water

Δθ is the temperature difference of water from 84.0°C to 55.0°C  

m = Q / cΔθ ,        Δθ = 84.0°C - 55.0°C = 29°C  

m = (4.05 x 10⁵ ) / (4.184 x 10³ x 29)  

m = 3.338 kg

Therefore, the mass of water required to heat the radiator is 3.338 kg