f(x)=-2(x+1)²+8
a. Vertex=
b. Y intercept=
C. X intercepts=
d. Axis of symmetry=
e. Direction of the opening=
f Domain=
g. Range=
h. Maximum value=
a. Vertex=
b. Y intercept=
C. X intercepts=
d. Axis of symmetry=
e. Direction of the opening=
f Domain=
g. Range=
h. Maximum value=
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How do you find the vertex of the graph of a quadratic function written in intercept form? Intercept form is also known as factored form: y=(x-p)(x-q) where p,q are the x-intercepts. One way to find the vertex is to rewrite in standard form: the vertex is located at where y=f(x).
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