we have to find height (h) of cable tower
So first of all
DEBC is a rectangle as all of the angles are of 90°
Therefore DC=EB=7m
AE=(h-7)m
Perpendicular (p)=AE
Base(b)=DE
We know,
Here,
We also know,
Perpendicular (p)=EB
Base (b)=DE
We know
Now equate both equation
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we have to find height (h) of cable tower
So first of all
DEBC is a rectangle as all of the angles are of 90°
Therefore DC=EB=7m
AE=(h-7)m
In ∆AED,
Perpendicular (p)=AE
Base(b)=DE
We know,
Here,
We also know,
In ∆DEB,
Perpendicular (p)=EB
Base (b)=DE
We know
Here,
We also know,
Now equate both equation
Height of cable tower=7(√3+1)m