Verified answer

[tex]\colorbox{blue}{★ANSWER★}[/tex]

For square PQRS side a=4

Area of square PQRS=a^2

[tex] = {(4)}^{2} cm^{2} \\ = 16 {cm}^{2} [/tex]

For each of the four quadrant I cut from each corner, radius r=1 cm.

[tex]Area \: of \: four \: quadrants = 4 (\frac{1}{4}\pi {r}^{2} )[/tex]

[tex] = \pi {r}^{2} [/tex]

[tex] = \frac{22}{7} \times 1 \times 1 \: cm^{2} [/tex]

[tex] =\frac{22}{7} [/tex]

For the circle cut in the middle part of the square, diameter=2 cm and hence radius r=1

[tex]Area \: of \: the \: circle = \pi {r}^{2} [/tex]

[tex] \frac{22}{7} \times 1 \times 1 \: cm {}^{2} [/tex]

[tex] = \frac{22}{7} cm^{2} [/tex]

Area of the remaining portion of the square

=Area of square PQRS-Area of four quadrant -Area of circle

=(16-22-22) cm^2

7 7

=68

— cm^2

7