Answer:
In A OAP & A OBP
A
OA = OB
(Both radius)
40°
PA = PB
(Lengths of tangent drawn from external point is equal)
OP = OP
(Common)
:: Δ ΟΑΡ = ΔΟΒΡ
(SSS congruency)
So, Z OPA = Z OPB
(CPCT)
So, Z OPA = < APB
== x 80° = 40°
In ΔΟΡΑ
Z POA+ZOPA + Z OAP = 180°
Z POA + 40° +90° = 180°
Z POA +130° = 180°
Z POA = 180° - 130⁰ = 50°
(Angle sum property of triangle)
So, A is the correct answer
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Answers & Comments
Answer:
In A OAP & A OBP
A
OA = OB
(Both radius)
40°
PA = PB
(Lengths of tangent drawn from external point is equal)
OP = OP
(Common)
:: Δ ΟΑΡ = ΔΟΒΡ
(SSS congruency)
So, Z OPA = Z OPB
(CPCT)
So, Z OPA = < APB
== x 80° = 40°
In ΔΟΡΑ
Z POA+ZOPA + Z OAP = 180°
Z POA + 40° +90° = 180°
Z POA +130° = 180°
Z POA = 180° - 130⁰ = 50°
(Angle sum property of triangle)
So, A is the correct answer