from a solid cylinder whose height is 16 cm and radius is 12 CM a conical cavity of height 8 centimetre and base radius 6 cm is hollowed out find the volume of the total surface area of the remaining solid
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Answer:
Step-by-step explanation:
given circle
2x2 + 2y2 - 6x+8y+1=0
dividing by 2 on both sides
x^2+y^2-3x+4y+1/2=0
comparing with std form we get
2g=-3
g=-3/2
2f=4
f=2
r=root of g^2+f^2-c=root of 9/4+4-1/2=√23/2 units
center (-g,-f)=(3/2,-2)
let the radius of new circle be r which has double area
π r^2=2π *33/4
r=√23/2 units
center will be same as it is concetric (3/2,-2)
therefore new circle would be
(x-3/2)^2+(y+2)^2=√((23/2) )^2
(x-3/2)^2+(y+2)^2=23/2