Since, ∆OPQ is a right-angled triangle, we have to find the radius of the circle (OP).
by Pythagoras Theorem, we get
(Hypotenuse)² = (Height)² + (Base)²
or, OQ² = OP² + PQ²
or, OQ² - PQ² = OP²
or, (25)² - (24)² = OP²
or, 625 - 576 = OP²
or, 49 = OP²
or, √49 = OP
or, 7 = OP
Therefore, the radius of the circle is 7 cm.
THE ANSWER IS ;7 cm
I. e radius is 7cm
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Since, ∆OPQ is a right-angled triangle, we have to find the radius of the circle (OP).
by Pythagoras Theorem, we get
(Hypotenuse)² = (Height)² + (Base)²
or, OQ² = OP² + PQ²
or, OQ² - PQ² = OP²
or, (25)² - (24)² = OP²
or, 625 - 576 = OP²
or, 49 = OP²
or, √49 = OP
or, 7 = OP
Therefore, the radius of the circle is 7 cm.
Verified answer
THE ANSWER IS ;7 cm
I. e radius is 7cm