Answer:
answer is 2cm
Step-by-step explanation:
4 - 3 = 1cm
1 × 2 = 2cm
Given :-
a circular sheet of radius 4 cm and radius of circle 3 cm is removed.
Outer Radius = R =4 cm
Inner Radius r=3 cm
Area of remaining sheet [tex]\tt =\pi R^{2}-\pi r^{2}[/tex]
[tex] \[ \begin{array}{l} \rm =\pi\left(R^{2}-r^{2}\right) \\ \\ \displaystyle \rm=\frac{22}{7}\left(4^{2}-3^{2}\right) \\\\ \\ \displaystyle \rm =\frac{22} {\cancel{7 \ }} \times \cancel{ 7 \ }\\\\ \\ \boxed{\color{magenta} \displaystyle \rm =22 \: cm ^{2}} \end{array} \][/tex]
Hence, area of remaining sheet is 22 cm².
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Answers & Comments
Answer:
answer is 2cm
Step-by-step explanation:
4 - 3 = 1cm
1 × 2 = 2cm
Verified answer
Given :-
a circular sheet of radius 4 cm and radius of circle 3 cm is removed.
Outer Radius = R =4 cm
Inner Radius r=3 cm
Area of remaining sheet [tex]\tt =\pi R^{2}-\pi r^{2}[/tex]
[tex] \[ \begin{array}{l} \rm =\pi\left(R^{2}-r^{2}\right) \\ \\ \displaystyle \rm=\frac{22}{7}\left(4^{2}-3^{2}\right) \\\\ \\ \displaystyle \rm =\frac{22} {\cancel{7 \ }} \times \cancel{ 7 \ }\\\\ \\ \boxed{\color{magenta} \displaystyle \rm =22 \: cm ^{2}} \end{array} \][/tex]
Hence, area of remaining sheet is 22 cm².