Answer:

[tex] Question [/tex]

Four years ago the father was three times as old as the son. The sum of their present ages is 72 years. The present age of the father is ?

12 =Sons age 4yrs ago.

12x3=Fathers age 4yrs ago.

36+4=present Fathers age.

Ans = 40.

i hope this helps you.

Verified answer

Answer:

fathers present age =x years.

sons present age =y years.

four years ago, fathers age =3× sons age.

(x−4)=(y−4)×3

x=3y−8. (i)

after 4 years, fathers age+ sons age =64

x+4+y+4=64

x+y=56 (ii)

solve for x

x=3×56−3x−8

4x=160

x = 160/4

x = 40