Answer:
The formula is: pH = -log[H3O+]. ( sorry I can't use subscript and superscript on tablet. here 3 is subscript and + is superscript)
hope it helps :)
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[tex]pH = -log[H₃O⁺].[/tex]
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Answer:
The formula is: pH = -log[H3O+]. ( sorry I can't use subscript and superscript on tablet. here 3 is subscript and + is superscript)
hope it helps :)
Verified answer
[tex]{\large{\bf{\pink{☞{\red{\underline{\orange{\mathfrak{Answer:}}}}}}}}}[/tex]
[tex]pH = -log[H₃O⁺].[/tex]