Hydraulic power is defined as flow multiplied by pressure. The hydraulic power supplied by a pump is: Power = (P x Q) ÷ 600 - where power is in kilowatts [kW], P is the pressure in bars, and Q is the flow in litres per minute. ** based upon 100% efficiency; 90% efficiency would equate to 75 ÷ 0.9 = 83.3kW.
Hydraulic power is defined as flow multiplied by pressure. The hydraulic power supplied by a pump is: Power = (P x Q) ÷ 600 - where power is in kilowatts [kW], P is the pressure in bars, and Q is the flow in litres per minute. ** based upon 100% efficiency; 90% efficiency would equate to 75 ÷ 0.9 = 83.3kW
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Answer:
Hydraulic power is defined as flow multiplied by pressure. The hydraulic power supplied by a pump is: Power = (P x Q) ÷ 600 - where power is in kilowatts [kW], P is the pressure in bars, and Q is the flow in litres per minute. ** based upon 100% efficiency; 90% efficiency would equate to 75 ÷ 0.9 = 83.3kW.
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Answer:
Hydraulic power is defined as flow multiplied by pressure. The hydraulic power supplied by a pump is: Power = (P x Q) ÷ 600 - where power is in kilowatts [kW], P is the pressure in bars, and Q is the flow in litres per minute. ** based upon 100% efficiency; 90% efficiency would equate to 75 ÷ 0.9 = 83.3kW