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[tex]\huge\fcolorbox{cyan}{white}{\color{red}{Solution}} \\ \\ \\ \mathtt{y = a \: cos(x + b)} \\ \\ \mathtt{ \frac{dy}{dx} = a \: \frac{d}{dx}(cosx + b) = - a \: sin(x + b) \times 1} \\ \\ \mathtt{ \frac{dy}{dx} = - a \: sin(x + b)} \\ \\ \tt{ \frac{ {d}^{2} y}{ {dx}^{2} } = a \: cos(x + b) = - y } \\ \\ \mathtt{ \frac{ {d}^{2}y }{ {dx}^{2}} \:+ y = 0} \\ \\ \\ \mathtt{{ \purple{hope} \: \blue{it} \: \pink{helps}}}[/tex]
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students your self
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[tex]\huge\fcolorbox{cyan}{white}{\color{red}{Solution}} \\ \\ \\ \mathtt{y = a \: cos(x + b)} \\ \\ \mathtt{ \frac{dy}{dx} = a \: \frac{d}{dx}(cosx + b) = - a \: sin(x + b) \times 1} \\ \\ \mathtt{ \frac{dy}{dx} = - a \: sin(x + b)} \\ \\ \tt{ \frac{ {d}^{2} y}{ {dx}^{2} } = a \: cos(x + b) = - y } \\ \\ \mathtt{ \frac{ {d}^{2}y }{ {dx}^{2}} \:+ y = 0} \\ \\ \\ \mathtt{{ \purple{hope} \: \blue{it} \: \pink{helps}}}[/tex]