Answer:

If these are consecutive terms, then double of middle term = first term+ third term

[tex] \orange{2(2k - 1) =( k + 9) +( 2k + 7)}[/tex]

[tex]4k - 2 = 3k + 16 \\ \red{\boxed{ k = 18}}[/tex]

Now,

[tex]1st \: term = 27 \\ 2nd \: term = 35 \\ 3r \: term = \: 43[/tex]

Sum = 27+35+43

= 70+35

= 105 answer

Plz thanks✌

Answer:

If these are consecutive terms, then double of middle term = first term+ third term

\orange{2(2k - 1) =( k + 9) +( 2k + 7)}2(2k−1)=(k+9)+(2k+7)

\begin{gathered}4k - 2 = 3k + 16 \\ \red{\boxed{ k = 18}}\end{gathered}

4k−2=3k+16

k=18

Now,

\begin{gathered}1st \: term = 27 \\ 2nd \: term = 35 \\ 3r \: term = \: 43\end{gathered}

1stterm=27

2ndterm=35

3rterm=43

Sum = 27+35+43

= 70+35

= 105 answer

Plz thanks ❤️