For number 7-8. Read the problem and answer the questions below:
On the morning of March 1, the electric meter reading was 26010 kWh. On the evening of March 31,the electric meter reading was 26175 kWh.
7 . How many kilowatt-hours of electricity were used during March ?
A . 165 kWh
B . 155 kWh
C . 551 kWh
D . 255 kWh
8 . If the electricity cost is Php 5.50 per kWh,how much is the electricity cost For March?
A ,Php 852.50
B . Php 907.50
C . Php 908.50
D . Php 905.20
5 points for each number, ty in advance^_^
Answers & Comments
Answer:
1.D
2.D
Step-by-step explanation:
Hope its helps
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Verified answer
Answer:
7. A. 165 kWh
8. B. Php 907.50
Step-by-step explanation:
First, subtract the previous reading to the current reading
26,175 - 26,010 = 165
Second, multiply the reading to the cost of electricity
165 x 5.50 = 907.50
Hope it helps:))