For items 19-22. The area of triangle A varies jointly as the base b and the altitude h. The area of
a triangle whose altitude is 24 cm and whose base is 4 cm is 48 cm2
19. Write the equation of the relation.
20. Solve for k.
21. What is the equation after solving the constant value?
22. Find the altitude of a triangle of equal area whose base is 6 cm.
a triangle whose altitude is 24 cm and whose base is 4 cm is 48 cm2
19. Write the equation of the relation.
20. Solve for k.
21. What is the equation after solving the constant value?
22. Find the altitude of a triangle of equal area whose base is 6 cm.
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Answer:
Formula of joint: A = kbh
19. Solve for k (constant of variation),
Step 1: Substitute: Let A = 48 cm, b = 4 cm, and h = 24 cm
48 cm = k (4 cm)(24 cm)
20. Step 2: Multiply: 48 = k (96)
Step 3: Divide both sides by 96 and cancel out: 48/96 = k
k = 1/2 or 0.5 (if you want it in decimal ver.)
21. Solving for unknown value of Area (A),
Step 4: Substitute: Let b = 6 cm, h = 16 cm, k = 1/2
22. Step 5: Use formula again: A = (1/2)(6 cm)(16 cm)
Step 6: Multiply: A = (3)(16)
A = 48 cm
Step-by-step explanation:
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