Verified answer

Answer:

1 sq unit

Step-by-step explanation:

For an Isosceles right triangle the formula of area for a given leg of length x is

[ A=(sin(alpha)x^2)/2 ]

[tex] {x}^{2} sin( \alpha ) \times \frac{1}{2} [/tex]

where alpha is the angle of Isosceles triangle.

Now, Putting values for x=

[tex] \sqrt{2 \: \\ } [/tex]

and

[tex] \alpha = 90[/tex]

we get the required answer