For all JEE aspirants. One important question for you all
2 mol of Hg(g) is combusted in a fixed volume bomb calorimeter with an excess of O2 at 298 K and 1 atm into HgO(s). During the reaction, temperature increases from 298.0 K to 312.8 K. If the heat capacity of the bomb calorimeter and enthalpy of formation of Hg(g) are 20.00 kJ K-1 and 61.32 kJ mol-1 at 298 K, respectively, the calculated standard molar enthalpy of formation of HgO(s) at 298 K is X kJ mol-1
. The value of |X| is
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