Answer:
Explanation:
H H H H H
| | | | |
i) H-C-C-C = C-C-H ii) 14 sigma 1 pi bonds iii) C1 sp3, C2 sp3, C3 sp2
| | | C4 sp2 , C5 sp3
H H H
iv) CH3C2CHCHCH3
v) Unsaturated
i) complete structure is as follows
H-C-C-C = C-C-H
| | |
ii) The number of sigma and pi bonds are
sigma = 14
pi = 1
iii) The type of hybridisation of each carbon atom is
C1 sp3, C2 sp3, C3 sp2 , C4 sp2 , C5 sp3
iv) The bond line formula of the compound is
CH3C2CHCHCH3
v)the compound in saturated or unsaturated
It is unsaturated as it has a pie bond.
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Verified answer
Answer:
Explanation:
H H H H H
| | | | |
i) H-C-C-C = C-C-H ii) 14 sigma 1 pi bonds iii) C1 sp3, C2 sp3, C3 sp2
| | | C4 sp2 , C5 sp3
H H H
iv) CH3C2CHCHCH3
v) Unsaturated
i) complete structure is as follows
H H H H H
| | | | |
H-C-C-C = C-C-H
| | |
H H H
ii) The number of sigma and pi bonds are
sigma = 14
pi = 1
iii) The type of hybridisation of each carbon atom is
C1 sp3, C2 sp3, C3 sp2 , C4 sp2 , C5 sp3
iv) The bond line formula of the compound is
CH3C2CHCHCH3
v)the compound in saturated or unsaturated
It is unsaturated as it has a pie bond.