Answer:
BDC = 50 (alternate angles)
x = 180 - 100 - 50=30
180-100 =80 (supplementary angles)
y = 180 - 80-40=60
x =30
y =60
Step-by-step explanation:
given: ∠A=40
∠B=50°
∠DOC=100
TO FIND : ∠D=Y° AND ∠C=X°
∠ABO=50
∴BDC = 50-------------- (alternate angles)
X+∠DOC+∠OBA=180
x+100°+50°=180°
x = 180 - 100 - 50
x=30
∠AOD=180-100
∠AOD=80
y+80+∠DAO=180
y = 180 - 80-40
y=60
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Answer:
BDC = 50 (alternate angles)
x = 180 - 100 - 50=30
180-100 =80 (supplementary angles)
y = 180 - 80-40=60
x =30
y =60
Answer:
x =30 and y =60
Step-by-step explanation:
given: ∠A=40
∠B=50°
∠DOC=100
TO FIND : ∠D=Y° AND ∠C=X°
SOLⁿ
∠ABO=50
∴BDC = 50-------------- (alternate angles)
FOR X
BY ANGLE SUM PROP
X+∠DOC+∠OBA=180
x+100°+50°=180°
x = 180 - 100 - 50
x=30
∵∠AOD+∠DOC=180 (supplementary angles)
∠AOD+100=180
∠AOD=180-100
∠AOD=80
NOW FOR Y
y+80+∠DAO=180
y = 180 - 80-40
y=60
∴x =30 and y =60