Step-by-step explanation:
Correct option is A)
Let a
n
=a+(n−1)d=55
⇒7+(n−1)×3=55
⇒(n−1)×3=48
⇒n−1=16
⇒n=17
Clearly 55 is the 17
th
term of given AP.Let the first term, common difference and the number of terms of an AP are a, d and n respectively.
Let the nth term of the AP be 55. i.e.,
T
=
55
We know that, the nth term of the AP,
a
+
(
−
1
)
d
.
i
Given that, first term (a) = 7 and common difference (d) = 10 – 7 = 3
⇒
7
×
3\)
55 = 7 + 3n - 3
55 = 4 + 3n
3n = 51
∴
n = 17
Since, n is a positive integer. Therefore, 55 is a term of the AP.
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Verified answer
Step-by-step explanation:
Correct option is A)
Let a
n
=a+(n−1)d=55
⇒7+(n−1)×3=55
⇒(n−1)×3=48
⇒n−1=16
⇒n=17
Clearly 55 is the 17
th
term of given AP.Let the first term, common difference and the number of terms of an AP are a, d and n respectively.
Let the nth term of the AP be 55. i.e.,
T
n
=
55
We know that, the nth term of the AP,
T
n
=
a
+
(
n
−
1
)
d
.
.
.
(
i
)
Given that, first term (a) = 7 and common difference (d) = 10 – 7 = 3
⇒
55
=
7
+
(
n
−
1
)
×
3\)
⇒
55 = 7 + 3n - 3
⇒
55 = 4 + 3n
⇒
3n = 51
∴
n = 17
Since, n is a positive integer. Therefore, 55 is a term of the AP.