Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.
To find : the two numbers
Let x and y be the two numbers required.
According to the question :
⇒2x+3y=92
⇒4x−7y=2
multiply the first equation by 2 , and subtract eqn (1) from eqn (2)
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Verified answer
Answer:
Given : two numbers are such that the sum of twice the first and thrice the second is 92, and four times the first exceeds seven times the second by 2.
To find : the two numbers
Let x and y be the two numbers required.
According to the question :
⇒2x+3y=92
⇒4x−7y=2
multiply the first equation by 2 , and subtract eqn (1) from eqn (2)
4x+6y=184
−(4x−7y=2) , we get
⇒13y=182
⇒y=13182=14
Put y=14 in (1)
2x+3y=92
⇒2x+3×14=92
⇒2x=92−42=50
∴x=250=25
∴x=25 and y=14
Step-by-step explanation:
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Answer:
92 *2 184
Step-by-step explanation:
thus is a right answer