The first number that is divisible by 4,5 and 6 in 200–600 is 240 .

Now lets just take the lcm of 4,5,6

Ie 60.

Which means. After every 60 , the number obtained is divisible by 4,5,6.

The last number divisible by 4,5,6 is 540(i am not considering 600 as the question says between 200–600 which is they are excluded)

Now using arthmatic progression

We can find the number of terms.

540=240+(n-1)60

300/60=n-1

N= 6

So the number of terms are 6!

Ps . We could have easily calculated it without the use of AP. By just taking the lcm and adding it untill it gets to 600.

Answer:

Didide 500 by 60 and the quotient obtained is 8. Similary divide 200 by 60, quotient otained is 3. This means there are 8 multiples of 60 from