Answer

f( x ) = abx² + ( b² - ac )x - bc

To find zeroes of f( x ) , we have to

take f( x ) = 0

abx² + ( b² - ac )x - bc = 0

abx² + b² x - acx - bc = 0

bx( ax + b ) - c( ax + b ) = 0

( ax + b ) ( bx - c ) = 0

ax + b = 0 or bx - c = 0

ax = - b or bx = c

x = -b/a or x = c/b

Therefore ,

-b/a , c/b are two zeroes of f( x ).

Step-by-step explanation:

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Verified answer

Answer:

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Find the zeros of the quadratic polynomial f(x)=abx²+(b²-ac)x-bc and verify the relationship between the zeros and it's coefficients