[tex]\: \: \: \: \: \: \sf{6x^{3} + 23x^{2} + 9x - 18 \: = \: 0}[/tex]
[tex]\sf{6x^{3} + 5x^{2} + 18x^{2} - 6x + 15x - 18 \: = \: 0}[/tex]
[tex]\sf{(6x^{3} + 5x^{2} - 6x) + (18x^{2} + 15x - 18) \: = \: 0}[/tex]
[tex]\sf{x(6x^{2} + 5x - 6) + 3(6x^{2} + 5x - 6) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \sf{(6x^{2} + 5x - 6)(x + 3) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \sf{(x + 3)(6x^{2} + 5x - 6) \: = \: 0}[/tex]
[tex]\sf{(x + 3)[6x^{2} + 9x - 4x - 6] \: = \: 0}[/tex]
[tex]\sf{(x + 3)[3x(2x + 3) - 2(2x + 3)] \: = \: 0}[/tex]
[tex]\: \: \: \: \sf{(x + 3)(2x + 3)(3x - 2) \: = \: 0}[/tex]
Now -
[tex]\sf{(x + 3) \: = \: 0 \: \: \: \: , \: \: \: \: (2x + 3) \: = \: 0 \: \: \: \: , \: \: \: \: (3x - 2) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \: \: \sf{x \: = \: - \: 3 \: , \: -\dfrac{3}{2} \: , \: \dfrac{2}{3}}[/tex]
[tex]\sf{zeroes \: of \: the \: polynomial \: are \: - \: 3 \: , \: -\dfrac{3}{2} \: and \: \dfrac{2}{3}.}[/tex]
Answer:
- 18 is the answer
I hope this help
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[tex]\: \: \: \: \: \: \sf{6x^{3} + 23x^{2} + 9x - 18 \: = \: 0}[/tex]
[tex]\sf{6x^{3} + 5x^{2} + 18x^{2} - 6x + 15x - 18 \: = \: 0}[/tex]
[tex]\sf{(6x^{3} + 5x^{2} - 6x) + (18x^{2} + 15x - 18) \: = \: 0}[/tex]
[tex]\sf{x(6x^{2} + 5x - 6) + 3(6x^{2} + 5x - 6) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \sf{(6x^{2} + 5x - 6)(x + 3) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \sf{(x + 3)(6x^{2} + 5x - 6) \: = \: 0}[/tex]
[tex]\sf{(x + 3)[6x^{2} + 9x - 4x - 6] \: = \: 0}[/tex]
[tex]\sf{(x + 3)[3x(2x + 3) - 2(2x + 3)] \: = \: 0}[/tex]
[tex]\: \: \: \: \sf{(x + 3)(2x + 3)(3x - 2) \: = \: 0}[/tex]
Now -
[tex]\sf{(x + 3) \: = \: 0 \: \: \: \: , \: \: \: \: (2x + 3) \: = \: 0 \: \: \: \: , \: \: \: \: (3x - 2) \: = \: 0}[/tex]
[tex]\: \: \: \: \: \: \: \: \: \: \: \: \sf{x \: = \: - \: 3 \: , \: -\dfrac{3}{2} \: , \: \dfrac{2}{3}}[/tex]
[tex]\sf{zeroes \: of \: the \: polynomial \: are \: - \: 3 \: , \: -\dfrac{3}{2} \: and \: \dfrac{2}{3}.}[/tex]
Answer:
- 18 is the answer
I hope this help