Step-by-step explanation:
4x^2-4x+1=0
4x^2-2x-2x+1=0
2x(2x-1)-1(2x-1)=0
(2x-1)(2x-1)
2x-1=0
2x=1
X=1/2;1/2
Alfa=1/2
beta=1/2
sum of the zeroes=Alfa+beta
=1/2+1/2
=1
product of the zeroes=(alfa)(beta)
=(1/2)(1/2)
=1/2
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Answers & Comments
4x2-2x-2x+1
2x(2x-1)-1(2x-1)
(2x-1)(2x-1)
Verify
Sum of zeroes =1/2+1/2=1=-b/a
Product of zeroes=1/2*1/2=1/4
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Step-by-step explanation:
4x^2-4x+1=0
4x^2-2x-2x+1=0
2x(2x-1)-1(2x-1)=0
(2x-1)(2x-1)
2x-1=0
2x=1
X=1/2;1/2
Alfa=1/2
beta=1/2
sum of the zeroes=Alfa+beta
=1/2+1/2
=1
product of the zeroes=(alfa)(beta)
=(1/2)(1/2)
=1/2