Answer:
Given polynomial is x² - 5
Let the zeros be a, B. (a > ẞ) x²-50 x2 = 5 = The coefficient of x is zero α + B = 0
a = √5,B=-√5
So, a+B=0, aẞ = =-5
(& of x² is 1).
Constant = aẞ = -5
Hence verified.
x² - 5x+4=0
x²-4x-x+4=0
x(x-4)-1(x-4) = 0
(x-1)(x-4)=0 = 1,
x = 1 x = 4
So the zeroes are = 1 and 4
[tex] \: [/tex]hope it helps
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Verified answer
Answer:
Given polynomial is x² - 5
Let the zeros be a, B. (a > ẞ) x²-50 x2 = 5 = The coefficient of x is zero α + B = 0
a = √5,B=-√5
So, a+B=0, aẞ = =-5
(& of x² is 1).
Constant = aẞ = -5
Hence verified.
Answer:
x² - 5x+4=0
x²-4x-x+4=0
x(x-4)-1(x-4) = 0
(x-1)(x-4)=0 = 1,
x = 1 x = 4
So the zeroes are = 1 and 4
[tex] \: [/tex]hope it helps