Step-by-step explanation:
To Find:
Formula used:
Solution:
x^2 + 5x + 6 = 0
Using the middle term splitting method, we have
x^2 + 3x + 2x + 6 = 0
x(x+3) + 2(x+3) = 0
Taking out the common terms, we get
(x+3)(x+2) = 0
x = -3 or x = -2
Zeroes of the given equation are -3 and -2.
1). Sum of roots = -b/a
-3 + (-2) = -5/1
-5 = -5
2). Product of roots = c/a
(-3)(-2) = 6/1
6 = 6
LHS = RHS
HENCE VERIFIED!
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Verified answer
Here you go :) do not copy from the web you’ll get caught instead write it like how I didStep-by-step explanation:
To Find:
Formula used:
Solution:
x^2 + 5x + 6 = 0
Using the middle term splitting method, we have
x^2 + 3x + 2x + 6 = 0
x(x+3) + 2(x+3) = 0
Taking out the common terms, we get
(x+3)(x+2) = 0
x = -3 or x = -2
Zeroes of the given equation are -3 and -2.
Verification:
1). Sum of roots = -b/a
-3 + (-2) = -5/1
-5 = -5
2). Product of roots = c/a
(-3)(-2) = 6/1
6 = 6
LHS = RHS
HENCE VERIFIED!