Answer:
The zero of the polynomial x3-8 is 2. Therefore, x3=8. Hence taking cube root for the given equation we get the root as 2.
Step-by-step explanation:
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The factors of constant term -8 is ±1, ±2, ±4 and ±8.
So,
p( 1 ) = (1)³ - 8
p ( 1 ) = 1 - 8
p ( 1 ) = -7
p ( 2 ) = (2)³ - 8
p ( 2 ) = 8 - 8
p ( 2 ) = 0
Therefore, the zero of polynomial x³ - 8 is 2.
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Answers & Comments
Answer:
The zero of the polynomial x3-8 is 2. Therefore, x3=8. Hence taking cube root for the given equation we get the root as 2.
Step-by-step explanation:
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Verified answer
The factors of constant term -8 is ±1, ±2, ±4 and ±8.
So,
p( 1 ) = (1)³ - 8
p ( 1 ) = 1 - 8
p ( 1 ) = -7
_______________________
p ( 2 ) = (2)³ - 8
p ( 2 ) = 8 - 8
p ( 2 ) = 0
Therefore, the zero of polynomial x³ - 8 is 2.