Digram :

[tex]\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{5}}\put(9,17.5){\sf{3}}\end{picture}[/tex]

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To find :

• Volume of cylinder

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Given :

• radius = 5m

• height = 3m

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Solution :

We know :-

[tex] \boxed{ \rm \: volume_{ \rm(cylinder)} = \pi {r}^{2} h}[/tex]

where :

r = radius

h = height

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So :-

[tex] \dashrightarrow\sf \: volume_{ \sf(cylinder)} = \pi {r}^{2} h[/tex]

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[tex] \dashrightarrow\sf \: volume_{ \sf(cylinder)} = \pi \times {5}^{2} \times 3[/tex]

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[tex] \dashrightarrow\sf \: volume_{ \sf(cylinder)} = \pi \times 25 \times 3[/tex]

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[tex] \dashrightarrow\sf \: volume_{ \sf(cylinder)} = \dfrac{22}{7} \times 75[/tex]

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[tex] \dashrightarrow\sf \: volume_{ \sf(cylinder)} = \dfrac{1650}{7} [/tex]

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[tex] \dashrightarrow\bold{\: volume_{ \sf(cylinder)} =235.71}[/tex]

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Know more :-

[tex] \begin{gathered} \small\boxed{\begin{array} {cc}\frak{ \red{ \underline{Formula \: of \: cylinder: }}} \\ \\ \\ \star \sf{}Area\:of\:Base\:and\:top =\pi r^2 \\ \\ \\\star \sf{}Curved \: Surface \: Area =2 \pi rh\\ \\ \\\star{} \sf{} Total \: Surface \: Area = 2 \pi r(h + r)\\ \\ \\ \star \sf{}Volume=\pi r^2h\end{array}}\end{gathered}[/tex]

See answer from website for better understandment