Answer:
Step-by-step explanation:
In ∆BPC y+90+25 =180
y=65
In ∆ADC
25+y+∠ADC=180
∠ADC=90 (X+∠ADC=180)
Therefore x=90
by external angle theorem
z=25+x
z=115
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Answer:
Step-by-step explanation:
In ∆BPC y+90+25 =180
y=65
In ∆ADC
25+y+∠ADC=180
∠ADC=90 (X+∠ADC=180)
Therefore x=90
by external angle theorem
z=25+x
z=115