If o is centre of the circle
hence OA= OD=OC=OB
and ∆ODC is a ispceles triangle with 42°
and ∆OAB congruent ∆ODC
hence x = 42°
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Verified answer
If o is centre of the circle
hence OA= OD=OC=OB
and ∆ODC is a ispceles triangle with 42°
and ∆OAB congruent ∆ODC
hence x = 42°
Please marka as brainliest :)