is the answer of above question see in this you have to draw perpendicular line as you perpendicular draw to line has 90degree so subtract from the other value that's 40and 50 and you will get two angle of triangle and then as sum of all sides of angle is 180 so add them up hope this will help you out if any more doubt or help surely you can message me on my Gmail [email protected] have a great day be happy and smilling:)
Answers & Comments
Answer:
140
Step-by-step explanation:
Given-
The lines AB & CD are parallel to each other.
AE & CE meet at E.
∠EAB=108
o ,∠ECD=112 o .To find out-
∠AEC=?
Solution-
the line EF is drawn such that
EF∥AB
i.eEF∥CD∵AB∥CD.
Now the sum of the same side internal angles=180
o∴∠AEF=180
o −∠EAB=180 o −108 o
=72 o &∠CEF=180 o−∠ECD=180 o
−112 o=68 o .∴∠AEC=x=∠AEF+∠CEF
=72 o+68 o=140 o .
is the answer of above question see in this you have to draw perpendicular line as you perpendicular draw to line has 90degree so subtract from the other value that's 40and 50 and you will get two angle of triangle and then as sum of all sides of angle is 180 so add them up hope this will help you out if any more doubt or help surely you can message me on my Gmail [email protected] have a great day be happy and smilling:)