AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CD
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40° ⇒ ∠BOD=∠BOE+∠EOD=50° +40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40° ⇒ ∠BOD=∠BOE+∠EOD=50° +40° ∴ ∠BOD=90°
Answers & Comments
AB∥CD [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CD
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40° ⇒ ∠BOD=∠BOE+∠EOD=50° +40°
AB∥CD [ Given ]∠ABO=50°. [ Given ]∠ODC=40°. [ Given ] Draw a line l such that,AB∥EF∥CDAB∥EF and BO is a tranversal.∴ ∠ABO=∠BOE [ Alternate angle ]∴ ∠BOE=50° EF∥CD and OD is transversal.∴ ∠EOD=∠CDO [ Alternate angle ]∴ ∠EOD=40° ⇒ ∠BOD=∠BOE+∠EOD=50° +40° ∴ ∠BOD=90°
Answer:
x = 90°
here you're answer