Step-by-step explanation:
for the points to be collinear
x1 (y2-y3) + x2( y3-y1) + x3 (y1-y2) = 0 ...(1)
now the points are A (1,5) B (K,1) and C (4,11) i.e,
x1 = 1 , y1= 5
x2 = ky2 = 1
x3 = 4y3 = 11
put these values in equation 1 .
1 (1-11) + k (11-5) + 4(5-1) = 0
-10 + 6k +16 = 0
6k +6 =0 .... 6k = -6
k= -1
Answer:
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Answers & Comments
Step-by-step explanation:
for the points to be collinear
x1 (y2-y3) + x2( y3-y1) + x3 (y1-y2) = 0 ...(1)
now the points are A (1,5) B (K,1) and C (4,11) i.e,
x1 = 1 , y1= 5
x2 = ky2 = 1
x3 = 4y3 = 11
put these values in equation 1 .
1 (1-11) + k (11-5) + 4(5-1) = 0
-10 + 6k +16 = 0
6k +6 =0 .... 6k = -6
k= -1
Answer:
Hi
Will u become my friend?