Answer:
It is given that 2:9::x:27
But, product of extremes = product of means
∴ 2×27=9×x
=54=9x
x=6
Hence, x=6
x=5
Step by step:
(2^x,27)=(32,27)
1st Method
⇒2^x=32
But 2^5=32
⇒2^x=2^5
When bases are equal, there exponents are also equal.
∴ x=5.
2nd Method
2^x=32
We know that ㏒a^b=b㏒a.
Taking log to both sides,
⇒ ㏒2^x=㏒32
⇒ x㏒2=㏒32
⇒ x=㏒32 ÷ log2
⇒ x= 1.5051499783 ÷ 0.3010299957
⇒ x ≈ 1.5 ÷ 0.3
∴ x=5
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Answers & Comments
Answer:
It is given that 2:9::x:27
But, product of extremes = product of means
∴ 2×27=9×x
=54=9x
x=6
Hence, x=6
Answer:
x=5
Step by step:
(2^x,27)=(32,27)
1st Method
⇒2^x=32
But 2^5=32
⇒2^x=2^5
When bases are equal, there exponents are also equal.
∴ x=5.
2nd Method
2^x=32
We know that ㏒a^b=b㏒a.
Taking log to both sides,
⇒ ㏒2^x=㏒32
⇒ x㏒2=㏒32
⇒ x=㏒32 ÷ log2
⇒ x= 1.5051499783 ÷ 0.3010299957
⇒ x ≈ 1.5 ÷ 0.3
∴ x=5