Answer:
[tex]p(x) = {x}^{2} - 1[/tex]
[tex]p( - 2) = ( - 2) {}^{2} - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: = ( - 2) \times ( - 2) - 1 \\ = 4 - 1 \: \: \: \: \: \: \: \: \: \: \: \: \\ = \boxed{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
x² - 1
p(x). =x²-1
p(-2) =(-2)²-1
=4-1
=3
therefore, the value of polynomial is 3.
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Answers & Comments
Answer:
[tex]p(x) = {x}^{2} - 1[/tex]
[tex]p( - 2) = ( - 2) {}^{2} - 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \: \: \: \: \: \: \: \: \: \: = ( - 2) \times ( - 2) - 1 \\ = 4 - 1 \: \: \: \: \: \: \: \: \: \: \: \: \\ = \boxed{3} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: [/tex]
Answer:
x² - 1
p(x). =x²-1
p(-2) =(-2)²-1
=4-1
=3
therefore, the value of polynomial is 3.