Let ( x - 1 ) = 0
Then
=> x = 1
Put x = 1 in the given polynomial
P ( x ) = k^2x^2 - 2kx - 3
P ( 1 ) = k^2 ( 1 )^2 - 2k ( 1 ) - 3
=> k^2 - 2k - 3 = 0
=> k^2 - 3k + k + 3 = 0
=> k ( k - 3 ) + 1 ( k + 3 ) = 0
=> ( k + 1 ) ( k - 3 ) = 0
=> ( k + 1 ) = 0 OR ( k - 3 ) = 0
=> k = - 1 OR k = 3
Therefore the value of k is - 1 , 3
Answer:
Which graph would correctly represent the result of
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Let ( x - 1 ) = 0
Then
=> x = 1
Put x = 1 in the given polynomial
P ( x ) = k^2x^2 - 2kx - 3
P ( 1 ) = k^2 ( 1 )^2 - 2k ( 1 ) - 3
=> k^2 - 2k - 3 = 0
=> k^2 - 3k + k + 3 = 0
=> k ( k - 3 ) + 1 ( k + 3 ) = 0
=> ( k + 1 ) ( k - 3 ) = 0
=> ( k + 1 ) = 0 OR ( k - 3 ) = 0
=> k = - 1 OR k = 3
Therefore the value of k is - 1 , 3
Answer:
Which graph would correctly represent the result of