3׳ + kx² + 5× - 27 ; (×+2)
×=-2
Solution :
3(-2)³ + k(-2)² + 5(-2) - 27 = 0
3(-8) + 4k - 10 - 27 = 0
4k - 24 - 10 - 27 = 0
4k - 61 = 0
4k = 61
K = 61/4
Answer:
im verry sorry friend please
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3׳ + kx² + 5× - 27 ; (×+2)
×=-2
Solution :
3(-2)³ + k(-2)² + 5(-2) - 27 = 0
3(-8) + 4k - 10 - 27 = 0
4k - 24 - 10 - 27 = 0
4k - 61 = 0
4k = 61
K = 61/4
Answer:
im verry sorry friend please
Solution:
x³ - 2x + k
(2)³ 2(2) + k = 0
8 - 4 + k = 0
4 + k = 0
k = -4