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Mochiny
@Mochiny
October 2022
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FIND THE VALUE OF EACH OF THE FOLLOWING POLYNOMIAL FUNCTION BY USING THE REMAINDER THEOREM.
THANK YOU IN ADVANCE
Answers & Comments
adatcerna
Answer
:
P(3) = -26
P(-3) = 161
P(1) = 0
P(2) = 0
Step-by-step
explana
tion
:
15 votes
Thanks 39
adatcerna
wait lng pk
adatcerna
wait lng po
adatcerna
3bstitute
Mochiny
sege po willing to wait
adatcerna
1.P(x) = 2x³ - 9x - 5x² - 8
Standard form:
P(x) = 2x³ - 5x² - 9x - 8
P(3) = 2(3)³ - 5(3)² - 9(3) - 8
P(3) = 54 - 45 - 27 - 8
P(3) = -26
adatcerna
2. P(x) = -4x³+5x²+8
x+3 → x=-3
P(x) = - 4x³ + 5x² + 8
P(-3) = - 4(-3)³ + 5(-3)² + 8
P(-3) = 108 + 45 + 8
P(-3) = 161
adatcerna
3. P(x) = x⁶ - x⁵ - x + 1
X-1 → x= 1
P(x) = x⁶ - x⁵ - x + 1
P(1) = (1)⁶ - (1)⁵ - (1) + 1
P(1) = 1 - 1 - 1 + 1
P(1) = 0
adatcerna
4. P(x) = 3x⁴ - 6x³ - 5x + 10
X-2 → x= 2
P(x) = 3x⁴ - 6x³ - 5x + 10
P(2)= 3(2)⁴-6(2)³-5(2)+10
P(2)= 48 - 48 - 10 + 10
P(2)= 0
adatcerna
yan na po 1-4
adatcerna
sorry po natagalan hirap kasi mag type haha
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Answers & Comments
Answer:
Step-by-step explanation:
Standard form:
P(x) = 2x³ - 5x² - 9x - 8
P(3) = 2(3)³ - 5(3)² - 9(3) - 8
P(3) = 54 - 45 - 27 - 8
P(3) = -26
x+3 → x=-3
P(x) = - 4x³ + 5x² + 8
P(-3) = - 4(-3)³ + 5(-3)² + 8
P(-3) = 108 + 45 + 8
P(-3) = 161
X-1 → x= 1
P(x) = x⁶ - x⁵ - x + 1
P(1) = (1)⁶ - (1)⁵ - (1) + 1
P(1) = 1 - 1 - 1 + 1
P(1) = 0
X-2 → x= 2
P(x) = 3x⁴ - 6x³ - 5x + 10
P(2)= 3(2)⁴-6(2)³-5(2)+10
P(2)= 48 - 48 - 10 + 10
P(2)= 0