[tex]\huge\tt ☃{SOLUTION:}[/tex]
[tex]{\color{gold}{\underline{\rule{100pt}{0pt}}}}{\color{hotpink}{\underline{\rule{100pt}{0pt}}}}[/tex]
cos^4A = (cos^2A)^2
sin^4A = (sin^2A)^2
cos^4A - sin^4A
= (cos^2A)^2 - (sin^2A)^2
= (cos^2A + sin^2A) (cos^2A - sin^2A)
= (1) × [cos^A - (1-cos^A)]
= cos^A - 1 + cos^A
= 2cos^A - 1
[tex]\bold{Thank ~you~:)}[/tex]
ans::::: =
2cos²A-1
This is the answer
If the ans is correct make me as brainliest
Thankyou❣️
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
[tex]\huge\tt ☃{SOLUTION:}[/tex]
[tex]{\color{gold}{\underline{\rule{100pt}{0pt}}}}{\color{hotpink}{\underline{\rule{100pt}{0pt}}}}[/tex]
cos^4A = (cos^2A)^2
sin^4A = (sin^2A)^2
cos^4A - sin^4A
= (cos^2A)^2 - (sin^2A)^2
= (cos^2A + sin^2A) (cos^2A - sin^2A)
= (1) × [cos^A - (1-cos^A)]
= cos^A - 1 + cos^A
= 2cos^A - 1
[tex]{\color{gold}{\underline{\rule{100pt}{0pt}}}}{\color{hotpink}{\underline{\rule{100pt}{0pt}}}}[/tex]
[tex]\bold{Thank ~you~:)}[/tex]
Verified answer
ans::::: =
2cos²A-1
This is the answer
If the ans is correct make me as brainliest
Thankyou❣️