Find the value of C(3,2).
To solve the combination problem we need to used the formula which is:
Solving the combination problem using the formula.
∴ Therefore, the value is 3 to the given combination.
#CarryOnLearning
Evaluate the combination nCr
A combination is a way to order or arrange a set or number of things (uniquely)
The formula for a combination of chóósing r ûnique wàys from n póssibiliti3s is:
nCr = n!/r!(n - r)!
where n is the number of items and r is the ûnique arràngemènts.
Plûgging in our nûmbers of n = 3 and r = 2, we get
3C2 = 3!/2!(3 - 2)!
Remèmber from our factorial lèsson that n! = n * (n - 1) * (n - 2) * ... * 2 * 1
Càlculàte the numerator n!:
n! = 3!
3! = 3 x 2 x 1
3! = 6
Càlculàte the fîrst denominator (n - r)!:
(n - r)! = (3 - 2)!
(3 - 2)! = 1!
1! = 1
Càlculàte the sècond denominator r!:
r! = 2!
2! = 2 x 1
2! = 2
Càlcûlate our combination value nCr for n = 3 and r = 2.
3C2 = 6/2 x 1
3C2 = 6/2
3C2 = 3
The Value of C(3,2) is 3
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Answers & Comments
Problem:
Find the value of C(3,2).
Solution:
To solve the combination problem we need to used the formula which is:
Solving the combination problem using the formula.
Answer:
∴ Therefore, the value is 3 to the given combination.
#CarryOnLearning
ANSWER:
Find the value of C(3,2).
Evaluate the combination nCr
A combination is a way to order or arrange a set or number of things (uniquely)
The formula for a combination of chóósing r ûnique wàys from n póssibiliti3s is:
nCr = n!/r!(n - r)!
where n is the number of items and r is the ûnique arràngemènts.
Plûgging in our nûmbers of n = 3 and r = 2, we get
3C2 = 3!/2!(3 - 2)!
Remèmber from our factorial lèsson that n! = n * (n - 1) * (n - 2) * ... * 2 * 1
Càlculàte the numerator n!:
n! = 3!
3! = 3 x 2 x 1
3! = 6
Càlculàte the fîrst denominator (n - r)!:
(n - r)! = (3 - 2)!
(3 - 2)! = 1!
1! = 1
1! = 1
Càlculàte the sècond denominator r!:
r! = 2!
2! = 2 x 1
2! = 2
Càlcûlate our combination value nCr for n = 3 and r = 2.
3C2 = 6/2 x 1
3C2 = 6/2
3C2 = 3
The Value of C(3,2) is 3