Answer:
Given : (1/3)³
To Find : Evaluate
Solution:
Law of exponent :
\begin{gathered}{{\text{a}}^{n}}\times {{a}^{-n}}=1\text{ or }{{\text{a}}^{n}}=\frac{1}{{{a}^{n}}} \\ & {{a}^{m}}\times {{a}^{n}}={{a}^{m+n}} \\ & \frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}} \\ & {{\left( {{a}^{m}} \right)}^{n}}={{\left( {{a}^{n}} \right)}^{m}}={{a}^{mn}} \\ & {{a}^{m}}\times {{b}^{m}}={{\left( ab \right)}^{m}} \\ & \frac{{{a}^{n}}}{{{b}^{n}}}={{\left( \frac{a}{b} \right)}^{n}} \\ & {{a}^{0}}=1 \\\end{gathered}
a
n
×a
−n
=1 or a
=
1
m
=a
m+n
m−n
(a
)
=(a
mn
×b
=(ab)
b
=(
0
=1
(1/3)³
= 1³/3³
1³ = 1 * 1 * 1 = 1
3³ = 3 * 3 * 3 = 27
= 1/27
(1/3)³ = 1/27
Learn More:
0.243^0.2×10^0.6=? Pls help me it's very urgent - Brainly.in
brainly.in/question/3246219
3⁴)² ÷ [3⁴ X 3⁵] : Evaluate.
Copyright © 2024 EHUB.TIPS team's - All rights reserved.
Answers & Comments
Answer:
Given : (1/3)³
To Find : Evaluate
Solution:
Law of exponent :
\begin{gathered}{{\text{a}}^{n}}\times {{a}^{-n}}=1\text{ or }{{\text{a}}^{n}}=\frac{1}{{{a}^{n}}} \\ & {{a}^{m}}\times {{a}^{n}}={{a}^{m+n}} \\ & \frac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}} \\ & {{\left( {{a}^{m}} \right)}^{n}}={{\left( {{a}^{n}} \right)}^{m}}={{a}^{mn}} \\ & {{a}^{m}}\times {{b}^{m}}={{\left( ab \right)}^{m}} \\ & \frac{{{a}^{n}}}{{{b}^{n}}}={{\left( \frac{a}{b} \right)}^{n}} \\ & {{a}^{0}}=1 \\\end{gathered}
a
n
×a
−n
=1 or a
n
=
a
n
1
a
m
×a
n
=a
m+n
a
n
a
m
=a
m−n
(a
m
)
n
=(a
n
)
m
=a
mn
a
m
×b
m
=(ab)
m
b
n
a
n
=(
b
a
)
n
a
0
=1
(1/3)³
= 1³/3³
1³ = 1 * 1 * 1 = 1
3³ = 3 * 3 * 3 = 27
= 1/27
(1/3)³ = 1/27
Learn More:
0.243^0.2×10^0.6=? Pls help me it's very urgent - Brainly.in
brainly.in/question/3246219
3⁴)² ÷ [3⁴ X 3⁵] : Evaluate.