These kinds of problems can be solved for by repeatedly multiplying and dividing n, in this case 15, by 1, 2, 3... r and n, n-q, n-2... n-r+1, respectively until we reach 1.
This is assuming that a combination of (n,r) does exist.
1365*1/15 = 91
91*2/14 = 13
13*3/13 = 3
3*4/12 = 1
With this, we can express 1365 as (15*14*13*12)/(4*3*2*1)
Answers & Comments
Step-by-step explanation:
These kinds of problems can be solved for by repeatedly multiplying and dividing n, in this case 15, by 1, 2, 3... r and n, n-q, n-2... n-r+1, respectively until we reach 1.
This is assuming that a combination of (n,r) does exist.
1365*1/15 = 91
91*2/14 = 13
13*3/13 = 3
3*4/12 = 1
With this, we can express 1365 as (15*14*13*12)/(4*3*2*1)
Therefore, r is 4
Answer:
4
Step-by-step explanation:
basta 4 yan promise. search nyo combination calculator tama yan