Answer:

A = {x:x is a natural number and multiple of 3} = {3,6,9…}

As, B = {x:x is a natural number less than 6} = {1,2,3,4,5,6}

A∪B = {1,2,4,5,3,6,9,12…}

∴, A∪B = {x:x=1,2,4,5 or a multiple of 3}

Or

A = {x:x is a natural number and 1<x≤6} = {2,3,4,5,6}

B = {x:x is a natural number and 6<x<10} = {7,8,9}

A∪B = {2,3,4,5,6,7,8,9}

∴, A∪B = {x:x∈N and 1<x<10}.

Step-by-step explanation:

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