Let the two numbers be a & b.
⇒ 3a + 2b = 36
⇒ 3a = 36 - 2b
⇒ a = (36 - 2b)/3 ...(1)
2nd case :-
⇒ 2a + b = 21
⇒ 2(36 - 2b)/3 + b = 21
⇒ (72 - 4b)/3 + b = 21
⇒ (72 - 4b + 3b)/3 = 21
⇒ 72 - b = 63
⇒ b = 72 - 63
⇒ b = 9
Now putting this value in (1) :-
⇒ a = {36 - 2(9)}/3
⇒ a = {36 - 18}/3
⇒ a = 18/3
⇒ a = 6
So to say,
➳ The two numbers are, 6 and 9
✭Thre times the first number + Twise the second number = 36
✭ Twice the first number + Second number = 21
➢ The two numbers?
❍ Let the first number be x. And, the second number be y.
❍ When three times the first number added to twice the second number, the sum is equal to 36.
Again, when twice the first number added to second number, the sum is equal to 21.
On equating both the equation (i) and (ii),
Substituting the value of x in (i),
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Answers & Comments
Two numbers are 6 and 9.
Solution
Let the two numbers be a & b.
⇒ 3a + 2b = 36
⇒ 3a = 36 - 2b
⇒ a = (36 - 2b)/3 ...(1)
2nd case :-
⇒ 2a + b = 21
⇒ 2(36 - 2b)/3 + b = 21
⇒ (72 - 4b)/3 + b = 21
⇒ (72 - 4b + 3b)/3 = 21
⇒ 72 - b = 63
⇒ b = 72 - 63
⇒ b = 9
Now putting this value in (1) :-
⇒ a = {36 - 2(9)}/3
⇒ a = {36 - 18}/3
⇒ a = 18/3
⇒ a = 6
So to say,
∴ Two numbers are 6 & 9 respectively.
Verified answer
Aɴꜱᴡᴇʀ
➳ The two numbers are, 6 and 9
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Gɪᴠᴇɴ
✭Thre times the first number + Twise the second number = 36
✭ Twice the first number + Second number = 21
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Tᴏ ꜰɪɴᴅ
➢ The two numbers?
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Sᴛᴇᴘꜱ
❍ Let the first number be x. And, the second number be y.
❍ When three times the first number added to twice the second number, the sum is equal to 36.
Equation :
Again, when twice the first number added to second number, the sum is equal to 21.
Equation :
On equating both the equation (i) and (ii),
Substituting the value of x in (i),
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